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Energy Requirements for Steel Cutting

Formulas to calculate the thermal energy needed to melt and vaporize steel in laser cutting processes

Total Energy to Melt Steel law
Q=mcΔT+mLf
Formes alternatives
  • Q=ρV(cΔT+Lf) — When volume V is known instead of mass m
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Qtotal thermal energy required
Sum of sensible heat to reach melting point and latent heat of fusion
J
mmass of steel to be cut
Mass depends on cut length, thickness, and kerf width
kg
cspecific heat capacity of steel
Typical value 500 J/(kg·K) for carbon steel
J/(kg·K)
\Delta Ttemperature change
From workshop temperature (~25°C) to melting point (~1500°C)
K
L_flatent heat of fusion
Typical value 2.7×10⁵ J/kg for steel
J/kg

Dimensions : [M][L]2[T]2

Exemple : Calculate energy to cut 1 m of 2 mm thick steel with 0.5 mm kerf width: Q = 7.85 kg/m³ × 0.002 m × 0.0005 m × 1 m × (500 J/kg·K × 1475 K + 2.7×10⁵ J/kg) ≈ 1.35 MJ

Power Density Threshold definition
Pd=PA=4Pπd2
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P_dpower density
Minimum required to initiate melting in steel
W/m²
Plaser power
Typical fiber laser: 500 W to 6 kW
W
dbeam diameter at workpiece
Focal spot size, typically 0.1-0.5 mm
m

Dimensions : [M][T]3

Exemple : For 1000 W laser with 0.2 mm focal spot: Pd = 4×1000/(π×(0.0002)²) ≈ 3.18×10¹⁰ W/m² (31.8 GW/m²)

Specific Cutting Energy definition
Es=QV=QwtL
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E_sspecific cutting energy
Energy required per unit volume of material removed
J/m³
Vvolume of material removed
V = w × t × L where w=kerf width, t=thickness, L=cut length
wkerf width
Typical 0.2-0.8 mm for steel laser cutting
m
tmaterial thickness
Common local workshop thickness: 1-5 mm
m
Lcut length
Length of cut profile
m

Dimensions : [M][L]1[T]2

Exemple : For 2 mm thick steel with 0.5 mm kerf cutting 1 m profile: Es = 1.35 MJ / (0.0005 m × 0.002 m × 1 m) ≈ 1.35×10⁹ J/m³

Cutting Speed and Power Relationship

Formulas relating laser power, cutting speed, and material properties for optimal cutting parameters

Maximum Cutting Speed approximation
vmax=PηEswt
Formes alternatives
  • vmax=PηHt — Where H is specific cutting energy per unit thickness (J/m²)
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v_{max}maximum cutting speed
Limited by energy delivery rate to the cut front
m/s
Plaser power
Effective power delivered to workpiece
W
\etaabsorption efficiency
Typical 0.7-0.9 for steel with fiber lasers
E_sspecific cutting energy
From previous calculation
J/m³

Dimensions : [L][T]1

Exemple : For 1500 W laser (η=0.8) cutting 2 mm steel with Es=1.35×10⁹ J/m³ and w=0.5 mm: vmax = (1500×0.8)/(1.35×10⁹×0.0005) ≈ 0.00178 m/s = 1.78 mm/s

Power Balance at Cut Front law
P=Esvwt
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Prequired laser power
Power needed to maintain cutting speed v
W
vcutting speed
Actual cutting speed used
m/s

Dimensions : [M][L]2[T]3

Exemple : To cut at 5 mm/s with Es=1.35×10⁹ J/m³, w=0.5 mm, t=2 mm: P = 1.35×10⁹ × 0.005 × 0.0005 × 0.002 ≈ 6.75 kW

Heat Input per Unit Length definition
H=Pv
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Hheat input per unit length
Critical parameter for weld quality and HAZ size
J/m

Dimensions : [M][L]2[T]2

Exemple : For P=2000 W and v=10 mm/s: H = 2000 / 0.01 = 200 kJ/m

Thermal Effects and Heat-Affected Zone

Formulas to estimate thermal effects on the material surrounding the cut

Heat-Affected Zone Width approximation
wHAZ=4αtintv
Formes alternatives
  • wHAZ=2αdv — When beam diameter d is known
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w_{HAZ}HAZ width
Width of material affected by heat but not melted
m
\alphathermal diffusivity of steel
Typical 1.2×10⁻⁵ m²/s for carbon steel
m²/s
t_{int}interaction time
Time beam dwells on a point: tint = d/v where d=beam diameter
s

Dimensions : [L]

Exemple : For α=1.2×10⁻⁵ m²/s, d=0.2 mm, v=5 mm/s: wHAZ = 2×√(1.2×10⁻⁵×0.0002/0.005) ≈ 0.22 mm

Cooling Rate approximation
dTdt=2πk(TT0)ρct2
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\frac{dT}{dt}cooling rate
Rate at which material cools after laser passes
K/s
kthermal conductivity
Typical 50 W/(m·K) for steel
W/(m·K)
Tinstantaneous temperature
Temperature at cooling time of interest
K
T_0ambient temperature
Workshop temperature ~298 K
K
tmaterial thickness
Thickness of steel plate
m

Dimensions : [Θ][T]1

Exemple : For 2 mm steel at 800°C cooling to 200°C: dT/dt ≈ -2π×50×(500)/(7850×500×0.002²) ≈ -1990 K/s

Peak Temperature Rise approximation
ΔTmax=2Pπktαπv
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\Delta T_{max}maximum temperature rise
Temperature increase above ambient at cut front
K

Dimensions : [Θ]

Exemple : For P=1000 W, k=50 W/m·K, t=2 mm, α=1.2×10⁻⁵ m²/s, v=10 mm/s: ΔTmax ≈ 2×1000/(π×50×0.002) × √(1.2×10⁻⁵/(π×0.01)) ≈ 1250 K

Beam Optics and Focus

Formulas describing laser beam focusing and depth of field for cutting applications

Focal Spot Diameter law
df=4λfπD
Formes alternatives
  • df=M24λfπD0 — Where M² is beam quality factor, D₀ is initial beam diameter
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d_ffocal spot diameter
Minimum beam diameter at focus
m
\lambdalaser wavelength
Fiber laser: 1.07 μm = 1.07×10⁻⁶ m
m
ffocal length
Typical 100-200 mm for cutting heads
m
Dbeam diameter at lens
Beam size before focusing optics
m

Dimensions : [L]

Exemple : For λ=1.07×10⁻⁶ m, f=150 mm, D=20 mm: df = 4×1.07×10⁻⁶×0.15/(π×0.02) ≈ 1.02×10⁻⁵ m = 10.2 μm

Depth of Focus definition
DOF=±8λπ(fD)2
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DOFdepth of focus
Range where spot size remains within 5% of minimum
m

Dimensions : [L]

Exemple : For λ=1.07×10⁻⁶ m, f=150 mm, D=20 mm: DOF = ±(8×1.07×10⁻⁶/π)×(0.15/0.02)² ≈ ±0.00153 m = ±1.53 mm

Beam Divergence Angle definition
θ=M2λπw0
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\thetahalf-angle divergence
Angle at which beam spreads after focus
rad
w_0beam waist radius
Radius at focal point: w₀ = df/2
m

Dimensions : 1

Exemple : For M²=1.2, λ=1.07×10⁻⁶ m, w₀=5.1×10⁻⁶ m: θ = 1.2×1.07×10⁻⁶/(π×5.1×10⁻⁶) ≈ 0.08 rad ≈ 4.6°

Material Properties at High Temperatures

Key thermal properties of steel relevant to laser cutting calculations

Thermal Diffusivity definition
α=kρc
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\alphathermal diffusivity
How quickly heat diffuses through material
m²/s
kthermal conductivity
Steel: 45-55 W/(m·K) at room temperature
W/(m·K)
\rhodensity
Steel: 7850 kg/m³
kg/m³

Dimensions : [L]2[T]1

Exemple : For k=50 W/m·K, ρ=7850 kg/m³, c=500 J/kg·K: α = 50/(7850×500) ≈ 1.27×10⁻⁵ m²/s

Energy Density for Vaporization definition
Ev=ρ(cΔTvap+Lv)
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E_vvaporization energy density
Energy required to vaporize steel
J/m³
L_vlatent heat of vaporization
Steel: ~6.0×10⁶ J/kg
J/kg
\Delta T_{vap}temperature change to vaporization
From 25°C to ~3000°C boiling point
K

Dimensions : [M][L]1[T]2

Exemple : For ρ=7850 kg/m³, c=500 J/kg·K, ΔTvap=2975 K, Lv=6.0×10⁶ J/kg: Ev = 7850×(500×2975 + 6.0×10⁶) ≈ 6.1×10¹⁰ J/m³

Absorption Coefficient at 1.07 μm definition
αabs105 to 106 m1
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\alpha_{abs}absorption coefficient
How deeply laser penetrates steel at fiber laser wavelength
m⁻¹

Dimensions : [L]1

Exemple : For α_abs=5×10⁵ m⁻¹, penetration depth = 1/α_abs ≈ 2 μm (very shallow, hence surface absorption dominates)

Sources

  1. en.wikipedia.org
  2. doi.org
  3. www.kzoomakers.org
  4. web.archive.org
  5. ui.adsabs.harvard.edu
  6. www.accurl.com
  7. www.twi-global.com
  8. chittak-laser.com
  9. vietducmetal.vn
  10. www.ctrlasers.co.uk
  11. books.google.com
  12. www.laserage.com